#!/usr/bin/perl # # Copyright © 2015-2020 by Vincent Slyngstad # # Permission is hereby granted, free of charge, to any person obtaining # a copy of this software and associated documentation files (the # "Software"), to deal in the Software without restriction, including # without limitation the rights to use, copy, modify, merge, publish, # distribute, sublicense, and/or sell copies of the Software, and to # permit persons to whom the Software is furnished to do so, subject to # the following conditions: # # The above copyright notice and this permission notice shall be # included in all copies or substantial portions of the Software. # # THE SOFTWARE IS PROVIDED "AS IS", WITHOUT WARRANTY OF ANY KIND, # EXPRESS OR IMPLIED, INCLUDING BUT NOT LIMITED TO THE WARRANTIES OF # MERCHANTABILITY, FITNESS FOR A PARTICULAR PURPOSE AND # NONINFRINGEMENT. IN NO EVENT SHALL THE AUTHORS LISTED ABOVE BE LIABLE # FOR ANY CLAIM, DAMAGES OR OTHER LIABILITY, WHETHER IN AN ACTION OF # CONTRACT, TORT OR OTHERWISE, ARISING FROM, OUT OF OR IN CONNECTION # WITH THE SOFTWARE OR THE USE OR OTHER DEALINGS IN THE SOFTWARE. # # Except as contained in this notice, the names of the authors above # shall not be used in advertising or otherwise to promote the sale, use # or other dealings in this Software without prior written authorization # from those authors. # Convert packed "cos" to disk images. # The bytes are packed. Each sector is 128 (RX01) # or 256 (RX02) bytes. There are 77 tracks and # 26 sectors/track. # This gives a size of 128*77*26 = 256256 bytes # for RX01, and 512512 bytes for RX02. # The RX8E (in 8 bit mode) just reads the 128 # byte sectors. This means a 256 word block # requires 3 sectors. # COS floppies are encoded with each of the # 3 sectors containing a byte of the 3 byte # encoding of a double word. We have to # Read all three sectors, then swizzle the # bits to reassemble the 256 words of a # block, which we can then output. # Track 0 is not used, so 76*26/3 gives a # capacity of 658 blocks. # Known data points: # Block 0 is sectors 1, 4, and 7. # Block 1 is sectors 10, 13, and 16. sub readsector { local($lsect) = @_; local($track, $sector, $spos); local($count); $track = 1 + int($lsect/26); # 26 sectors/track # Interleave 3 within the track. $sector = ($lsect*3) % 26; # Now find and read it. $spos = (($track*26)+$sector) * $size; #printf "$lsect->$track $sector %lo\n", $spos; seek(INPUT, $spos, 0) || die "seek($flp): $!"; $count = read(INPUT, $buf, $size); die "read($flp): $!" if $count < 0; last unless $count; die "read($flp): wrong count $!" if $count != $size; return unpack("C*", $buf); } foreach $flp (@ARGV) { open(INPUT, $flp) || die "$flp: $!"; binmode(INPUT); $f = $flp; $f =~ s/[.]cos$//; $f .= ".dsk"; ($_, $_, $_, $_, $_, $_, $_, $size) = stat(INPUT); die "$flp: volume is not a floppy image" if $size % (77*16); $size /= 77 * 26; # Calculate sector size die "$flp: volume is not an RX01 image" unless ($size == 128); $ds = $size * 3 / 4; # die "$f: exists" if -f $f; open(OUTPUT, ">$f") || die "$f: $!"; binmode(OUTPUT); # RX01: 26*76 = 1976 sectors. 1976 sectors == 658 blocks. # RX02: Packed RX02 format doesn't seem reasonable, as each OS/8 # block would be 1.5 sectors! # The last couple of sectors are not accessible, as # they are not part of a triplet. for ($block = 0; $block < 658; $block++) { $lsect = 3*$block; @bufh = &readsector($lsect); $lsect++; @buf = &readsector($lsect); $lsect++; push(@buf, &readsector($lsect)); #printf "output: %lo\n", tell(OUTPUT); for ($i = 0; $i < 128; $i++) { # The missing bits of @buf are packed into # bufh: $buf[2*$i] += (($bufh[$i] >> 4)<<8); $buf[2*$i+1] += (($bufh[$i] & 017)<<8); } print OUTPUT pack("S*", @buf); } } exit 0;